You can use $facet operator for this. To understand the concept, let us create a collection with document. The query to create a collection with document is as follows −
> db.totalDocumentDemo.insertOne({"InstructorId":100,"InstructorName":"Larry","InstructorFav
ouriteSubject":["Java","MongoDB","Python"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c76e6701e9c5dd6f1f78274")
}
> db.totalDocumentDemo.insertOne({"InstructorId":200,"InstructorName":"Sam","InstructorFav
ouriteSubject":["SQL Server","C#","Javascript"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c76e69c1e9c5dd6f1f78275")
}Display all documents from a collection with the help of find() method. The query is as follows −
> db.totalDocumentDemo.find().pretty();
Output
{
"_id" : ObjectId("5c76e6701e9c5dd6f1f78274"),
"InstructorId" : 100,
"InstructorName" : "Larry",
"InstructorFavouriteSubject" : [
"Java",
"MongoDB",
"Python"
]
}
{
"_id" : ObjectId("5c76e69c1e9c5dd6f1f78275"),
"InstructorId" : 200,
"InstructorName" : "Sam",
"InstructorFavouriteSubject" : [
"SQL Server",
"C#",
"Javascript"
]
}Here is the query to get a count of total documents from a collection −
> db.totalDocumentDemo.aggregate([
... {
... $facet:{
... Alldata:[{$match:{}}],
... totalDocument: [{ $count: 'totalDocument' }]
... }
... }
... ]).pretty();The following is the output displaying the count of documents −
Output
{
"Alldata" : [
{
"_id" : ObjectId("5c76e6701e9c5dd6f1f78274"),
"InstructorId" : 100,
"InstructorName" : "Larry",
"InstructorFavouriteSubject" : [
"Java",
"MongoDB",
"Python"
]
},
{
"_id" : ObjectId("5c76e69c1e9c5dd6f1f78275"),
"InstructorId" : 200,
"InstructorName" : "Sam",
"InstructorFavouriteSubject" : [
"SQL Server",
"C#",
"Javascript"
]
}
],
"totalDocument" : [
{
"totalDocument" : 2
}
]
}